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How do we solve equations that involve fractions? Before we get started, I am assuming you already know how to solve equations by balancing: you must do the exact same thing to both sides. So lets have a look at how to solve equations involving fractions. EXAMPLE: (2f + 8) / 3 = 6. The whole of 2f plus 8 has been divided by 3. We need to move this ‘3’ first so that everything is on the same level. No denominators. So multiply both sides by 3. Multiplying by 3 and dividing by 3 on the left hand side means that the 3's cancel each other on the left hand side. This leaves a simple linear equation to solve. 2f + 8 = 6 X 3 which simplifies to 2f + 8 = 18. Solve it: 2f = 10, so answer f=5. Easy! As always, check your answer. Substitute f=5 into the original question. EXAMPLE 2: (20 + 7e) / 2 = 2e + 7. Start by multiplying both sides by 2 to remove the '2' from the denominator on the left hand side. This means the times by 2 and divide by 2 on the left hand side cancel each other out. We now have this equation: 20 + 7e = 2(2e + 7). Expand the bracket on the right hand side and solve. 20 + 7e = 4e + 14. Simplify and solve: 3e = -6. Answer: e = -2.
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Watch this video to discover how to plot straight lines onto a graph.
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In this video we’re going to look at how to simplify algebraic expressions. Before we get started on simplifying, a few things to remember:
(1) we always use a use a curly x for the letter x in algebra.
(2) We don’t really use the mul
In algebra, we replace a letter with numbers in the process known as substitution. Given the formula A = 1/2bh, if the base is 5cm and the height is 10cm, then the area is ½ X 5 X 10 because we have replaced the b with 5 and the h with 10. You just need to be be careful with negative numbers: it is