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Solving Quadratics By Factorising | Algebra | Maths | FuseSchool

Click here to see more videos: https://alugha.com/FuseSchool Quadratics usually have an x-squared, an x term and a number on it’s own (known as a constant). There are a few different ways to solve quadratics: factorising, using the quadratic formula or by completing the square. In this video we look at solving by factorising. Solving just means to find values of x that satisfy the quadratic. Usually there will be 2 solutions, but sometimes there is just 1 and sometimes there are no solutions. The solutions are also known as roots. When we factorise, we usually end up with two brackets. E.g x^2 + 2x - 8 factorises to become (x + 4)(x - 2). To solve this factorised quadratic, we make each bracket equal to zero and solve the mini-equations from there. x + 4 = 0 and x - 2 = 0. Solve these and we get x = -4 and x = 2. Two different solutions (or roots). If we plotted this quadratic, these two roots are where the curve crosses the x-axis. Our teachers and animators come together to make fun & easy-to-understand videos in Chemistry, Biology, Physics, Maths & ICT. VISIT us at www.fuseschool.org, where all of our videos are carefully organised into topics and specific orders, and to see what else we have on offer. Comment, like and share with other learners. You can both ask and answer questions, and teachers will get back to you. These videos can be used in a flipped classroom model or as a revision aid. Twitter: https://twitter.com/fuseSchool This Open Educational Resource is free of charge, under a Creative Commons License: Attribution-NonCommercial CC BY-NC ( View License Deed: http://creativecommons.org/licenses/by-nc/4.0/ ). You are allowed to download the video for nonprofit, educational use. If you would like to modify the video, please contact us: info@fuseschool.org

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Equation Of Parallel Lines | Graphs | Maths | FuseSchool

In this video, we are going to look at parallel lines. To find the equation of parallel lines, we still use the y=mx + c equation, and because they have the same gradient, we know straight away that the gradient ‘m’ will be the same. We then just need to find the missing y-intercept ‘c’ value. VISI